로우데이타의 현재재고 합산 방법을 어떻게 해야하는지..ㅠㅠ 0 4 3,747

by 이카루스 [SQL Query] LAG LEAD oracle [2020.01.30 17:35:46]


안녕하세요
매일 현재재고 합계를 위해 LAG, LEAD 함수를 써도 신통치 않아 염치없이 도움을 요청합니다.. ㅠㅠ
 
-- 소스 ---
with t1 as (

select  'aaaa1111' as 상품코드, '20191225' as 일자, 0 as 현재재고, 0 as 입고, 0 as 출고  from dual
union all select  'aaaa1111' , '20191226' , 0 , 10, 0   from dual
union all select  'aaaa1111' , '20191227' , 0 , 30, 10   from dual
union all select  'aaaa1111' , '20191228' , 0 ,  0, 10   from dual
union all select  'aaaa1111' , '20191229' , 0 ,  0, 10   from dual
union all select  'aaaa1111' , '20191230' ,  0 ,  0, 10   from dual
union all select  'aaaa1111' , '20191231' , 0 ,  5,  0   from dual
union all select  'aaaa1111' , '20200101' , 0 , 5,   0   from dual
union all select  'aaaa1111' , '20200102' , 0 , 5, 0   from dual
union all select  'aaaa1111' , '20200103' , 0 , 5, 5   from dual
union all select  'aaaa1111' , '20200103' , 0 , 0, 5   from dual
)
select * from t1;


---타켓 /  현재재고합산 결과 ----

with t2 as (

select  'aaaa1111' as 상품코드, '20191225' as 일자, 0 as 현재재고, 0 as 입고, 0 as 출고  from dual
union all select  'aaaa1111' , '20191226' , 10 , 10, 0   from dual
union all select  'aaaa1111' , '20191227' , 30 , 30, 10   from dual
union all select  'aaaa1111' , '20191228' , 20 ,  0, 10   from dual
union all select  'aaaa1111' , '20191229' , 10 ,  0, 10   from dual
union all select  'aaaa1111' , '20191230' ,  0 ,  0, 10   from dual
union all select  'aaaa1111' , '20191231' , 5 ,  5,  0   from dual
union all select  'aaaa1111' , '20200101' , 10 , 5,   0   from dual
union all select  'aaaa1111' , '20200102' , 15 , 5, 0   from dual
union all select  'aaaa1111' , '20200103' , 15 , 5, 5   from dual
union all select  'aaaa1111' , '20200103' , 10 , 0, 5   from dual
)
select * from t2;

 

by 마농 [2020.01.30 17:54:34]

분석함수는 순차적으로 실행되는게 아니라 한번에 실행됩니다.
따라서 바로 이전값만 참조하는 LAG 가 아닌 SUM 함수를 이용해 보세요.


by 이카루스 [2020.01.31 16:39:51]

넵 말씀대로 기억났습니다 감사합니다!!


by jkson [2020.01.31 07:40:58]

20100103이 두 개인데 일자별 순번 컬럼은 없나요?


with t1 as (
select  'aaaa1111' as 상품코드, '20191225' as 일자, 0 as 현재재고, 0 as 입고, 0 as 출고  from dual
union all select  'aaaa1111' , '20191226' , 0 , 10, 0   from dual
union all select  'aaaa1111' , '20191227' , 0 , 30, 10   from dual
union all select  'aaaa1111' , '20191228' , 0 ,  0, 10   from dual
union all select  'aaaa1111' , '20191229' , 0 ,  0, 10   from dual
union all select  'aaaa1111' , '20191230' ,  0 ,  0, 10   from dual
union all select  'aaaa1111' , '20191231' , 0 ,  5,  0   from dual
union all select  'aaaa1111' , '20200101' , 0 , 5,   0   from dual
union all select  'aaaa1111' , '20200102' , 0 , 5, 0   from dual
union all select  'aaaa1111' , '20200103' , 0 , 5, 5   from dual
union all select  'aaaa1111' , '20200103' , 0 , 0, 5   from dual
)
select 상품코드
, 일자
, sum(입고) OVER(PARTITION BY 상품코드 ORDER BY 일자, rownum) - sum(출고) OVER(PARTITION BY 상품코드 ORDER BY 일자, rownum) 현재재고--일자별순번컬럼 없어서 rownum으로 대체
, 입고
, 출고 
from t1
 

 


by 이카루스 [2020.01.31 16:40:09]

넵 말씀대로 해결했습니다 감사합니다!!!

댓글등록
SQL문을 포맷에 맞게(깔끔하게) 등록하려면 code() 버튼을 클릭하여 작성 하시면 됩니다.
로그인 사용자만 댓글을 작성 할 수 있습니다. 로그인, 회원가입