Oracle 10g Pivot 관련 질문입니다. 1 2 17,386

by 하트세이버 [SQL Query] pivot [2014.02.25 12:35:33]


SELECT 'Store01' AS CD, 10  AS WON, 1 AS YMD FROM DUAL UNION ALL 
SELECT 'Store02' AS CD, 20  AS WON, 2 AS YMD FROM DUAL UNION ALL 
SELECT 'Store03' AS CD, 30  AS WON, 3 AS YMD FROM DUAL UNION ALL 
SELECT 'Store04' AS CD, 300  AS WON, 4 AS YMD FROM DUAL UNION ALL 
SELECT 'Store05' AS CD, 54 AS WON, 5 AS YMD FROM DUAL UNION ALL 
SELECT 'Store06' AS CD, 5  AS WON, 6 AS YMD FROM DUAL UNION ALL 
SELECT 'Store07' AS CD, 8 AS WON, 7 AS YMD FROM DUAL

해당 쿼리의 결과를

Store01 | Store02Store03Store04Store05Store06Store07

   10           20          30         300        54          5            8

    1             2           3            4           5           6            7

위의 형태의 결과값으로 얻는 방법을 알고 싶습니다.
by 마농 [2014.02.25 15:20:39]
WITH t AS
(
SELECT 'Store01' AS cd, 10 AS won, 1 AS ymd FROM dual
UNION ALL SELECT 'Store02',  20, 2 FROM dual
UNION ALL SELECT 'Store03',  30, 3 FROM dual
UNION ALL SELECT 'Store04', 300, 4 FROM dual
UNION ALL SELECT 'Store05',  54, 5 FROM dual
UNION ALL SELECT 'Store06',   5, 6 FROM dual
UNION ALL SELECT 'Store07',   8, 7 FROM dual
)
-- 2. Min(Decode(를 이용한 Pivot
SELECT DECODE(lv, 1, 'Won', 2, 'Ymd') gbn
     , MIN(DECODE(cd, 'Store01', v)) Store01
     , MIN(DECODE(cd, 'Store02', v)) Store02
     , MIN(DECODE(cd, 'Store03', v)) Store03
     , MIN(DECODE(cd, 'Store04', v)) Store04
     , MIN(DECODE(cd, 'Store05', v)) Store05
     , MIN(DECODE(cd, 'Store06', v)) Store06
     , MIN(DECODE(cd, 'Store07', v)) Store07
  FROM (-- 1. Decode(lv 를 이용한 UnPivot
        SELECT lv
             , cd
             , DECODE(lv, 1, won, 2, ymd) v
          FROM t
             , (SELECT LEVEL lv FROM dual CONNECT BY LEVEL <= 2)
        )
 GROUP BY lv
 ORDER BY lv
;

by 하트세이버 [2014.02.25 15:40:48]
감사합니다. 마농님 덕분에 해결할 수 있게 되었네요..
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